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The circumference of a circle is 22 cm. The area of its quadrant (in cm^{2}) is

#### Options

A.`77/2`

B.`77/4`

C.`77/8`

D.`77/16`

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#### Solution

Let the radius of the circle be *r* cm.

**Given:** Circumference of circle = 22 cm

`therefore 2pir=22cm` `[therefore\text{Circumference of circle = 2pir}]`

`rArrr=22/(2pi)cm`

`rArrr=(22xx7)/(2xx22)cm`

`rArrr=7/2cm`

Area of quadrant of circle

`=1/4(\text{Area of circle})`

`=pi_4^1xxr^2`

`=1/4xx22/7xx7/2xx7/2cm^2`

`=77/2cm^2`

Hence, the correct answer is C.

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