Answer 1

 80080 cm³

Let R and r be the radii of the top and base of the bucket, respectively, and let h be its height. 

Then,

R = 35 cm, r = 14 cm , h = 40 cm

R = 35 cm, r = 14 cm, h = 40 cm

Volume of the bucket = Volume of the frustum of the cone

`=1/3pi"h"["R"^2 +"r"^2+"Rr" ] "cm"^3`

`= 1/3 xx22/7xx40xx[(35)^2 + (14)^2 + (35xx14)] "cm"^3`

`=((880)/(21)xx1911) "cm"^3`

= 80080 cm³ 

Hence, the volume of the bucket is 80080 cm³.