Question

The cell in which the following reaction occurs:

`2Fe^(3+) (aq) + 2I^(-) (aq) ---> 2Fe^(2+) (aq) + I_2 (s)` has `E_"cell"^@` = 0.236 V at  298 K. Calculate the standard Gibbs energy of the cell reaction. (Given : 1 F = 96,500 C mol⁻¹)

Answer 1

Here n = 2, `E_"cell"^@ = 0.236 V`, T = 298 K

We know that

`triangle G^@ = -nFE_"cell"^@`

= −2 × 96500 × 0.236

= −45548 J mol⁻¹

= −45.548 kJ mol⁻¹