#### Question

The Cartestation equation of line is `(x-6)/2=(y+4)/7=(z-5)/3` find its vector equation.

#### Solution

`(x-6)/2=(y+4)/7=(z-5)/3`

Line is passing through the point (6,–4,5) with dr^{s} 2, 7, 3

Equation of line in vector form is

`vecr=(6veci-4vecj+5veck)+lambda(2 veci+7 vecj+3vec k)`

Is there an error in this question or solution?

#### APPEARS IN

Solution The Cartestation Equation of Line Is (x-6)/2=(y+4)/7=(z-5)/3 Find Its Vector Equation. Concept: Equation of a Line in Space.