Answer 1

Let the base of ∆ = 4x m
and height of ∆ = 5x m
area of ∆ = 40 m²

∵ `1/2 "base" xx "height" = "area of"  Delta`

`1/2 xx 4x xx 5x = 40`

`10x^2 = 40`

`x^2 = 4`

x = `sqrt(4)`

x = 2

base = 4x = `4 xx 2 = 8` m

height = 5x = `5 xx 2 = 10` m

∴ 8 m; 10 m