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The Areas of Two Similar Triangles Are in Respectively 9 Cm2 and 16 Cm2. the Ratio of Their Corresponding Sides is (A) 3 : 4 (B) 4 : 3 (C) 2 : 3 (D) 4 : 5 - Mathematics

MCQ

The areas of two similar triangles are in respectively 9 cm2 and 16 cm2. The ratio of their corresponding sides is

Options

  •  3 : 4

  • 4 : 3

  •  2 : 3

  • 4 : 5

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Solution

Given: Areas of two similar triangles are 9cm2 and 16cm2.

To find: Ratio of their corresponding sides.

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

`\text{ar(tringle 1)}/\text{ar(tringle 2)}=(\text{side1}/\text{side2})^2`

`9/12=(\text{side1}/\text{side2})^2`

Taking square root on both sides, we get

\[\frac{\text{side1}}{\text{side2}} = \frac{3}{4}\]

So, the ratio of their corresponding sides is 3 : 4.

Hence the correct answer is `a`

Concept: Triangles Examples and Solutions
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APPEARS IN

RD Sharma Class 10 Maths
Chapter 7 Triangles
Q 2 | Page 131
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