The area of the square that can be inscribed in a circle of radius 8 cm is ______.
Options
256 cm2
128 cm2
`64sqrt(2)` cm2
64 cm2
Solution
The area of the square that can be inscribed in a circle of radius 8 cm is 128 cm2.
Explanation:
Given, radius of circle, r = OC = 8cm.
∴ Diameter of the circle = AC = 2 × OC = 2 × 8 = 16 cm
Which is equal to the diagonal of a square.
Let side of square be x.
In right-angled ΔABC,
AC2 = AB2 + BC2 ......[By Pythagoras theorem]
⇒ `(16)^2 = x^2 + x^2`
⇒ 256 = `x^2 + x^2`
⇒ `x^2 = 128`
∴ Area of square = `x^2 = 128 cm^2`
Alternative Method:
Radius of circle (r) = 8 cm
Diameter of circle (d) = 2r = 2 × 8 = 16 cm
Since, square inscribed in circle.
∴ Diagonal of the square = Diameter of circle
Now, Area of square = `("Diagonals")^2/2`
= `(16)^2/2`
= `256/2`
= 128 cm2