The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is ______. - Mathematics

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The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is ______.

Options

  • `sqrt(15)` cm2 

  • `sqrt(15/2)` cm2

  • `2sqrt(15)` cm2

  • `4sqrt(15)` cm2

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Solution

The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is `sqrt(15)` cm2.

Explanation: 

a = 2, b = 4, c = 4

s = `(a + b + c)/2`

⇒ s = `(2 + 4 + 4)/2 = 10/2` = 5.

Area (Δ) = `sqrt(s(s - a)(s - b)(s - c))`

⇒ Area (Δ) = `sqrt(5(5 - 2)(5 - 4)(5 - 4))`

⇒ Area (Δ) = `sqrt(5 xx 3 xx 1 xx 1`

⇒ Area (Δ) = `sqrt(15)` cm2

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Chapter 12: Heron's Formula - Exercise 12.1 [Page 114]

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NCERT Exemplar Mathematics Class 9
Chapter 12 Heron's Formula
Exercise 12.1 | Q 8 | Page 114

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