Maharashtra State Board course SSC (English Medium) Class 10th Board Exam
Share
Notifications

View all notifications

The Area of a Minor Sector of a Circle is 3.85 Cm2 and the Measure of Its Central Angle is 36°. Find the Radius of the Circle . - Geometry

Login
Create free account


      Forgot password?

Question

The area of a minor sector of a circle is 3.85 cmand the measure of its central angle is 36°. Find the radius of the circle.

Solution

Area of minor sector of the circle = 3.85 cm2
The measure of a central angle, θ = 36º
Let the radius of the circle be r cm.
Now,
Area of minor sector = 3.85 cm

\[\Rightarrow \frac{\theta}{360° } \times \pi r^2 = 3 . 85\]

\[ \Rightarrow \frac{36° }{360 ° } \times \frac{22}{7} \times r^2 = 3 . 85\]

\[ \Rightarrow r = \sqrt{\frac{3 . 85 \times 360°  \times 7}{36°  \times 22}}\]

\[ \Rightarrow r = \sqrt{12 . 25} = 3 . 5 cm\]

Thus, the radius of the circle is 3.5 cm . 

  Is there an error in this question or solution?

APPEARS IN

 Balbharati Solution for Balbharati Class 10 Mathematics 2 Geometry (2018 to Current)
Chapter 7: Mensuration
Practice set 7.3 | Q: 11 | Page no. 155
Solution The Area of a Minor Sector of a Circle is 3.85 Cm2 and the Measure of Its Central Angle is 36°. Find the Radius of the Circle . Concept: Perimeter and Area of a Circle.
S
View in app×