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The Area of the Incircle of an Equilateral Triangle of Side 42 Cm is - Mathematics


The area of the incircle of an equilateral triangle of side 42 cm is


  • \[22\sqrt{3} c m^2\]

  •  231 cm2

  • 462 cm2

  • 924 cm2

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Let ABC be the equilateral triangle such that AB = BC = CA = 42 cm. Also, let O be the centre and r be the radius of its incircle.

AB, BC and CA are tangents to the circle at M, N and P.

`∴ OM=ON=OP=r`

Area of ΔABC = Area (ΔOAB) + Area (ΔOBC) + Area (ΔOCA) 

`⇒ sqrt3/4(42)^2=1/2xxrxxAB+1/2xxrxxBC+1/2xxrxx CA`

`⇒ sqrt3/4xx42xx42=1/2 r(AB+BC+CA)`

`⇒ 441sqrt3=1/2xxrxx(42+42+42)`




`⇒ r=7sqrt3 cm`

Area of the circle `= pir^2=22/7 (7sqrt3)^2=22/7xx147=462 cm^2`

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RD Sharma Class 10 Maths
Chapter 13 Areas Related to Circles
Q 9 | Page 69
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