Answer 1

`CH_3COONa + H_2O -> CH_3COOH + NaOH`

`CH_3COO^(-) + Na^(+) + H_2O -> CH_3COOH + Na^(+) +OH^(-)`

`:. CH_3COO^(-1) + H_2O -> CH_3COOH + OH^(-)`

∵ `OH^(-)` are left in the solution

∴ Sodium acetate on hydrolysis gives basic solution.