The angle of depression of a car parked on the road from the top of a 150 m high tower is 30°. The distance of the car from the tower (in metres) is
`(B) 150sqrt 3`
Correct answer: A
Let AB be the tower and BC be distance between tower and car. Let θ be the angle of depression of the car.
According to the given information,
`tan theta =`
Hence, distance between the tower and car is `50 sqrt3`