# The Ages of Sonu and Monu Are in the Ratio 7 : 5. Ten Years Hence, the Ratio of Their Ages Will Be 9 : 7. Find Their Present Ages. - Mathematics

Numerical

The ages of sonu and Monu are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.

#### Solution

It is given that the ratio of the ages of Sonu and Monu is 7: 5 .
Let the present ages of Sonu and Monu be 7x and 5x years .
After ten years:
Age of Sonu = 7x + 10 years
Age of Monu = 5x + 10 years
According to the question,
$\frac{7x + 10}{5x + 10} = \frac{9}{7}$
or 49x + 70 = 45x + 90
or 49x - 45x = 90 - 70
or 4x = 20
or x = 5
∴ Present age of Sonu =$7 \times 5 = 35\text{ years }.$
Present age of Monu =$5 \times 5 = 25\text{ years }.$

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#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 9 Linear Equation in One Variable
Exercise 9.4 | Q 12 | Page 30