Advertisement Remove all ads

The Ages of Sonu and Monu Are in the Ratio 7 : 5. Ten Years Hence, the Ratio of Their Ages Will Be 9 : 7. Find Their Present Ages. - Mathematics

Numerical

The ages of sonu and Monu are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.

Advertisement Remove all ads

Solution

It is given that the ratio of the ages of Sonu and Monu is 7: 5 . 
Let the present ages of Sonu and Monu be 7x and 5x years . 
After ten years: 
Age of Sonu = 7x + 10 years 
Age of Monu = 5x + 10 years
According to the question, 
\[\frac{7x + 10}{5x + 10} = \frac{9}{7}\]
or 49x + 70 = 45x + 90
or 49x - 45x = 90 - 70
or 4x = 20
or x = 5
∴ Present age of Sonu =\[ 7 \times 5 = 35\text{ years }. \]
 Present age of Monu =\[ 5 \times 5 = 25\text{ years }. \]

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

RD Sharma Class 8 Maths
Chapter 9 Linear Equation in One Variable
Exercise 9.4 | Q 12 | Page 30
Advertisement Remove all ads

Video TutorialsVIEW ALL [1]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×