Question

The 4^th term from the end of the AP: –11, –8, –5, ..., 49 is ______.

Options

• 37

• 40

• 43

• 58

Answer 1

The 4^th term from the end of the AP: –11, –8, –5, ..., 49 is 40.

Explanation:

 We know that, the n^th term of an AP from the end is 

`a_n = l - (n - 1)d`   ......(i)

Here, l = Last term and l = 49

Common difference `d = - 8 - (-11)`

= `-8 + 11`

= 3

From equation (i)

`a_4 = 49 - (4 - 1)3`

= `49 - 9`

= 40