# The 4th term from the end of the AP: –11, –8, –5, ..., 49 is ______. - Mathematics

MCQ
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The 4th term from the end of the AP: –11, –8, –5, ..., 49 is ______.

• 37

• 40

• 43

• 58

#### Solution

The 4th term from the end of the AP: –11, –8, –5, ..., 49 is 40.

Explanation:

We know that, the nth term of an AP from the end is

a_n = l - (n - 1)d   ......(i)

Here, l = Last term and l = 49

Common difference d = - 8 - (-11)

= -8 + 11

= 3

From equation (i)

a_4 = 49 - (4 - 1)3

= 49 - 9

= 40

Concept: Arithmetic Progression
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#### APPEARS IN

NCERT Mathematics Exemplar Class 10
Chapter 5 Arithematic Progressions
Exercise 5.1 | Q 13 | Page 46
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