The 17th Term of an AP Exceeds Its 10th Term by 7. Find the Common Difference. - Mathematics

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Sum

The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

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Solution

We know that,

For an A.P., an = a + (n − 1) d

a17 = a + (17 − 1) d

a17 = a + 16d

Similarly, a10 = a + 9d

It is given that

a17 − a10 = 7

(a + 16d) − (a + 9d) = 7

7d = 7

`d = 7/7`

d = 1

Therefore, the common difference is 1

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Chapter 5: Arithmetic Progressions - Exercise 5.2 [Page 106]

APPEARS IN

NCERT Mathematics Class 10
Chapter 5 Arithmetic Progressions
Exercise 5.2 | Q 10 | Page 106
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