# Ten Men, Working for 6 Days of 10 Hours Each, Finish 5/21 of a Piece of Work. How Many Men Working at the Same Rate and for the Same Number of Hours Each Day, Will Be Required to Complete - Mathematics

Sum

Ten men, working for 6 days of 10 hours each, finish 5/21 of a piece of work. How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 days?

#### Solution

Work does one =5/21

Remaining work =1-5/21=16/21

5/21 of a work can be done in 6 days working 10 hours a day by = 10 m

1 work can be done in 6 days working 10 hours a day by =(10xx21)/5

1 work can be done in 1 day working 10 hours a day by =(10xx21xx6)/5 men

16/21 work can be done in 8 days working 10 hours a day by =(10xx21xx6xx16)/(5xx21xx8) = 24 men

Concept: Concept for Unitary Method (With Only Direct Variation Implied)
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#### APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 10 Direct and Inverse Variations
Exercise 10 (D) | Q 13 | Page 130