#### Question

A metal sphere cools at the rate of 4°C / min. when its temperature is 50°C. Find its rate of cooling at 45°C if the temperature of surroundings is 25°C.

clickto share

#### Solution

Given that for the metal sphere

`((d theta)/dt)_1=4^@`C/min,

`theta_1=50^@C, theta_2=45^@ and theta_0=25^C`

By Newton's law of cooling,

`((d theta)/dt)=k(theta-theta_0)`

`therefore((d theta)/dt)_1/((d theta)/dt)_2=((theta_1-theta_0))/((theta_2-theta_0)`

`therefore((d theta)/dt)_1/((d theta)/dt)_2=((50^@-25^0))/((45^@-25^@)`

`therefore ((d theta)/dt)_2=20^@/25^@*((d theta)/dt)_1=20^@/25^@*4=3.2`

`therefore ((d theta)/dt)_2=3.2^@`C/min

Is there an error in this question or solution?

#### Related QuestionsVIEW ALL [12]

#### Reference Material

Solution for question: A metal sphere cools at the rate of 4°C / min. when its temperature is 50°C. Find its rate of cooling at 45°C if the temperature of surroundings is 25°C. concept: Temperature and Heat. For the courses HSC Science (General) , HSC Science (Computer Science), HSC Science (Electronics), HSC Science (General)