HSC Science (General) 12th Board ExamMaharashtra State Board
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Explain a graphical method to determine activation energy of a reaction - HSC Science (General) 12th Board Exam - Chemistry

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Question

Explain a graphical method to determine activation energy of a reaction.

Solution

The Arrhenius equation is given by

`k=Ae^((-E_a)/(RT))`

On taking logarithms of both sides, we get

`log_nk=log_nA-E_a/(RT)`

or

`log_10k=-E_a/(2.303RT)+log_10A`

`log_10k=-E_a/(2.303R) times (1/T)+log_10A`

The rate constant of a reaction is determined at various temperatures.

log10 k is plotted against the reciprocal of temperature. The graphical
representation is

The slope of the straight line graph is 

`–(Ea)/(2.303R)`

from which the activation energy can be calculated.

 
 
 
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APPEARS IN

 2015-2016 (March) (with solutions)
Question 1.4 | 2.00 marks

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Solution Explain a graphical method to determine activation energy of a reaction Concept: Temperature Dependence of the Rate of a Reaction.
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