The line y = x + 1 is a tangent to the curve y2 = 4x at the point
(A) (1, 2)
(B) (2, 1)
(C) (1, −2)
(D) (−1, 2)
The equation of the given curve is y2 = 4x
Differentiating with respect to x, we have:
Hence, the line y = x + 1 is a tangent to the given curve at the point (1, 2).
The correct answer is A.