#### Question

Show that the equation of normal at any point t on the curve *x* = 3 cos t – cos^{3}t and y = 3 sin t – sin^{3}t is 4 (y cos^{3}t – sin^{3}t) = 3 sin 4t

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Solution for question: Show that the equation of normal at any point t on the curve x = 3 cos t – cos3t and y = 3 sin t – sin3t is 4 (y cos3t – sin3t) = 3 sin 4t concept: Tangents and Normals. For the courses CBSE (Arts), CBSE (Commerce), CBSE (Science)