Solution - Tangents and Normals



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Show that the equation of normal at any point t on the curve x = 3 cos t – cos3t and y = 3 sin t – sin3t is 4 (y cos3t – sin3t) = 3 sin 4t


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Reference Material

Solution for concept: Tangents and Normals. For the courses 12th CBSE (Arts), 12th CBSE (Commerce), 12th CBSE (Science)