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In the Given Figure, Pt Touches the Circle with Centre O at Point R. Diameter Sq is Produced to Meet the Tangent Tr at P. Given ∠Spr = X° and ∠Qrp = Y°; (Ii) Write an Expression Connecting X and Y. - Mathematics

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Question

In the given figure, PT touches the circle with centre O at point R. Diameter SQ is produced to meet the tangent TR at P.
Given ∠SPR = x° and ∠QRP = y°;
Prove that:
(i) ∠ORS = y°
(ii) Write an expression connecting x and y.

Solution

`∠`QRP = `∠`OSR = y (angles in alternate segment)

But OS = OR (Radii of the same circle)
∴`∠`ORS = `∠`OSR = y
∴ OQ = OR (radii of same circle)
∴ OQR = `∠` ORQ=  90° - y …………(i) (Since OR ⊥ PT )
But in Δ PQR ,
Ext `∠` OQR = x  + y ……(i)
From (i) and (ii)
x + y  = 90°- y
⇒ x  + 2 y = 90° 

  Is there an error in this question or solution?
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APPEARS IN

 Selina Solution for Concise Mathematics for Class 10 ICSE (2020 (Latest))
Chapter 18: Tangents and Intersecting Chords
Exercise 18 (A) | Q: 21 | Page no. 275
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In the Given Figure, Pt Touches the Circle with Centre O at Point R. Diameter Sq is Produced to Meet the Tangent Tr at P. Given ∠Spr = X° and ∠Qrp = Y°; (Ii) Write an Expression Connecting X and Y. Concept: Tangent Properties - If a Line Touches a Circle and from the Point of Contact, a Chord is Drawn, the Angles Between the Tangent and the Chord Are Respectively Equal to the Angles in the Corresponding Alternate Segments.
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