#### Question

Chords AB and CD of a circle when extended meet at point X. Given AB = 4 cm, BX = 6 cm and XD = 5 cm, calculate the length of CD.

#### Solution

We know that XB.XA = XD.XC

Or, XB.(XB + BA) = XD.(XD + CD)

Or, 6(6 + 4) = 5(5 + CD)

Or, 60 = 5(5 + CD)

Or, 5 + CD = `60/5`= 12

Or, CD = 12 − 5 = 7 cm.

Is there an error in this question or solution?

Solution Chords Ab and Cd of a Circle When Extended Meet at Point X. Given Ab = 4 Cm, Bx = 6 Cm and Xd = 5 Cm, Calculate the Length of Cd. Concept: Tangent Properties - If a Chord and a Tangent Intersect Externally, Then the Product of the Lengths of Segments of the Chord is Equal to the Square of the Length of the Tangent from the Point of Contact to the Point of Intersection.