The Given Figure Shows a Circle with Centre O and Bcd is Tangent to It at C. Show That: ∠Acd + ∠Bac = 90° - ICSE Class 10 - Mathematics
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The given figure shows a circle with centre O and BCD is tangent to it at C. Show that: ∠ACD + ∠BAC = 90°
BCD is the tangent and OC is the radius.
∴ OC ⊥ BD
⇒ `∠`OCD = 90°
⇒ `∠`OCA + `∠`ACD = 90°
But in ΔOCA
OA = OC (radii of same circle)
∴ `∠` OAC + `∠` OAC
`∠` OAC + `∠`ACD = 90°
⇒ `∠`BAC + `∠`ACD = 90°
Is there an error in this question or solution?
Solution The Given Figure Shows a Circle with Centre O and Bcd is Tangent to It at C. Show That: ∠Acd + ∠Bac = 90° Concept: Tangent to a Circle.