Taking Force, Length and Time to Be the Fundamental Quantities, Find the Dimensions of Momentum. - Physics

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Short Note
Sum

Taking force, length and time to be the fundamental quantities, find the dimensions of momentum. 

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Solution

 Momentum = mv = (force/acceleration) × velocity
\[\text{ Acceleration }= \left[ {LT}^{- 2} \right] \text{ and } \text{ velocity }= \left[ {LT}^{- 1} \right]\]
\[\therefore \left[\text{ Momentum }\right] = \frac{\left[ F \right]}{\left[ {LT}^{- 2} \right]} \times \left[ {LT}^{- 1} \right] = \left[ FT \right]\].

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Chapter 1: Introduction to Physics - Exercise [Page 10]

APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1
Chapter 1 Introduction to Physics
Exercise | Q 7.3 | Page 10

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