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# Taking Force, Length and Time to Be the Fundamental Quantities, Find the Dimensions of Energy. - Physics

Sum

Taking force, length and time to be the fundamental quantities, find the dimensions of energy.

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#### Solution

Energy
$= \frac{1}{2}m v^2 = \frac{\text{ force}}{\text{acceleration}} \times \left( \text{velocity}\right)^2$
$\therefore \left[ \text{Energy} \right] = \frac{\left[ F \right]}{\left[ {LT}^{- 2} \right]} \times \left[ {LT}^{- 1} \right]^2 = \left[ FL \right]$

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#### APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 1 Introduction to Physics
Exercise | Q 7.4 | Page 10
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