Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11

Taking Force, Length and Time to Be the Fundamental Quantities, Find the Dimensions of Density . - Physics

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Sum

Taking force, length and time to be the fundamental quantities, find the dimensions of density .

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Solution

Density

\[= \frac{m}{v} = \frac{\left( \text{ force/acceleration } \right)}{\text{ volume}}\]
\[ \left[\text{ Acceleration }\right] = \left[ {LT}^{- 2} \right] \text{ and [volume] } ={\left[ L^3 \right]}$\]
\[ \therefore \text{ [Density]} = \frac{\left[ F/ {LT}^{- 2} \right]}{\left[ L^3 \right]} = \frac{F}{L^4 T^{- 2}} = \left[ {FL}^{- 4} T^2 \right]\]

Concept: Fundamental Forces in Nature
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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1
Chapter 1 Introduction to Physics
Exercise | Q 7.1 | Page 10

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