# Take Away: 2 3 a C − 5 7 a B + 2 3 B C from 3 2 a B − 7 4 a C − 5 6 B C - Mathematics

Take away:

$\frac{2}{3}ac - \frac{5}{7}ab + \frac{2}{3}bc\text { from } \frac{3}{2}ab - \frac{7}{4}ac - \frac{5}{6}bc$

#### Solution

The difference is given by:

$\left( \frac{3}{2}ab - \frac{7}{4}ac - \frac{5}{6}bc \right) - \left( \frac{2}{3}ac - \frac{5}{7}ab + \frac{2}{3}bc \right)$

$= \frac{3}{2}ab-\frac{7}{4}ac-\frac{5}{6}bc-\frac{2}{3}ac+\frac{5}{7}ab-\frac{2}{3}bc$

$= \frac{3}{2}ab + \frac{5}{7}ab - \frac{7}{4}ac - \frac{2}{3}ac - \frac{5}{6}bc - \frac{2}{3}bc$ (Collecting like terms )

= $\left( \frac{21 + 10}{14} \right)ab + \left( \frac{- 21 - 8}{12} \right)ac + \left( \frac{- 5 - 4}{6} \right)bc$

$=\frac{31}{14}ab-\frac{29}{12}ac-\frac{3}{2}bc$           (Combining like terms )

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Class 8 Maths
Chapter 6 Algebraic Expressions and Identities
Exercise 6.2 | Q 3.5 | Page 5