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The Total Energy of Free Surface of a Liquid Drop is 2π Times the Surface Tension of the Liquid. What is the Diameter of the Drop? (Assume All Terms in Si Unit). - Physics

Question

The total energy of free surface of a liquid drop is 2π times the surface tension of the liquid. What is the diameter of the drop? (Assume all terms in SI unit).

Solution

Given: E = 2πT

To find: Diameter of drop (d)

Formula: E = TΔA

Calculation: From formula,

Delta A=E/T

Delta A=(2piT)/T

Delta A=2pi

we know ,Delta A=4pir^2

Substituting in equation (1)

2pi=4pir^2

4r^2=2

r^2=2/4=1/2

r^2=0.5

r=sqrt(0.5)=0.71m

d=2r

=2(0.71)

d=1.414 m

The diameter of the drop is 1.414 m.

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