#### Question

The total energy of free surface of a liquid drop is 2π times the surface tension of the liquid. What is the diameter of the drop? (Assume all terms in SI unit).

#### Solution

Given: E = 2πT

To find: Diameter of drop (d)

Formula: E = TΔA

Calculation: From formula,

`Delta A=E/T`

`Delta A=(2piT)/T`

`Delta A=2pi`

we know ,`Delta A=4pir^2`

Substituting in equation (1)

`2pi=4pir^2`

`4r^2=2`

`r^2=2/4=1/2`

`r^2=0.5`

`r=sqrt(0.5)=0.71m`

`d=2r`

=2(0.71)

d=1.414 m

The diameter of the drop is 1.414 m.

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#### APPEARS IN

Solution The Total Energy of Free Surface of a Liquid Drop is 2π Times the Surface Tension of the Liquid. What is the Diameter of the Drop? (Assume All Terms in Si Unit). Concept: Surface Tension.