HSC Science (Computer Science) 12th Board ExamMaharashtra State Board
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Calculate Surface Tension of Water at 25°C - HSC Science (Computer Science) 12th Board Exam - Physics

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Question

The surface tension of water at 0°C is 75.5 dyne/cm. Calculate surface tension of water at 25°C.

(α for water = 2.7×10-3/°C)

Solution

Given:

T0 = 75.5 dyne/cm

αwater = 2.7 × 10-3/°C

To find:

Surface tension of water at 25°C

Formula:

T1 = T0(1 - αΔt)

Solution:

T25 = T0(1 - αΔt)

T25 = T0(1 - α(25 - 0))

T25 = 75.5(1 - 2.7 × 10-3 × 25)

T25 = 75.5(1 - 0.0675)

T25 = 70.4 dyne/cm

The surface tension of water at 25°C is 70.4 dyne/cm.

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APPEARS IN

 2014-2015 (March) (with solutions)
Question 2.6 | 2.00 marks

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Solution Calculate Surface Tension of Water at 25°C Concept: Surface Tension.
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