The surface tension of water at 0°C is 75.5 dyne/cm. Calculate surface tension of water at 25°C.
(α for water = 2.7×10-3/°C)
T0 = 75.5 dyne/cm
αwater = 2.7 × 10-3/°C
Surface tension of water at 25°C
T1 = T0(1 - αΔt)
T25 = T0(1 - αΔt)
T25 = T0(1 - α(25 - 0))
T25 = 75.5(1 - 2.7 × 10-3 × 25)
T25 = 75.5(1 - 0.0675)
T25 = 70.4 dyne/cm
The surface tension of water at 25°C is 70.4 dyne/cm.
What is the excess pressure inside a bubble of soap solution of radius 5.00 mm, given that the surface tension of soap solution at the temperature (20 °C) is 2.50 × 10–2 N m–1? If an air bubble of the same dimension were formed at depth of 40.0 cm inside a container containing the soap solution (of relative density 1.20), what would be the pressure inside the bubble? (1 atmospheric pressure is 1.01 × 105 Pa).
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