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# A Hemispherical Bowl Made of Brass Has Inner Diameter 10.5 Cm. Find the Cost of Tin- Plating It on the Inside at the Rate of Rs. 4 per 100 Cm^2 - CBSE Class 9 - Mathematics

ConceptSurface Area of a Sphere

#### Question

A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin- plating
it on the inside at the rate of Rs. 4 per 100 cm^2

#### Solution

Given
Inner diameter of hemisphere bowl -10.5cm

Radius -  (10.5)/2cm - 5.25 cm .

Surface area of hemispherical bowl - 2πr

- 2[22/7] × (5.25)^2 cm ^2

- 173 .25 cm^2

Cost of tin planning 100cm^2 area = Rs. 4

Cost of tin planning 173.25 cm^2 area = Rs .((4 xx173.25)/100)

= Rs. 6.93

Thus, The cost of tin plating the inner side of hemisphere bowl is Rs .6 93

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for Mathematics for Class 9 by R D Sharma (2018-19 Session) (2018 to Current)
Chapter 21: Surface Areas and Volume of a Sphere
Ex.21.10 | Q: 5 | Page no. 8
Solution A Hemispherical Bowl Made of Brass Has Inner Diameter 10.5 Cm. Find the Cost of Tin- Plating It on the Inside at the Rate of Rs. 4 per 100 Cm^2 Concept: Surface Area of a Sphere.
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