#### Question

A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin- plating

it on the inside at the rate of Rs. 4 per 100 `cm^2`

#### Solution

Given

Inner diameter of hemisphere bowl -10.5cm

Radius - `(10.5)/2`cm - 5.25 cm .

Surface area of hemispherical bowl - 2πr

- 2`[22/7] × (5.25)^2 cm ^2`

-` 173 .25 cm^2`

Cost of tin planning 100`cm^2` area = Rs. 4

Cost of tin planning `173.25 cm^2` area = Rs .`((4 xx173.25)/100)`

= Rs. 6.93

Thus, The cost of tin plating the inner side of hemisphere bowl is Rs .6 93

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Solution A Hemispherical Bowl Made of Brass Has Inner Diameter 10.5 Cm. Find the Cost of Tin- Plating It on the Inside at the Rate of Rs. 4 per 100 `Cm^2` Concept: Surface Area of a Sphere.