#### Question

Monica has a piece of Canvas whose area is 551 m2. She uses it to have a conical tent made, with a base radius of 7m. Assuming that all the stitching margins and wastage incurred while cutting, amounts to approximately 1 m2. Find the volume of the tent that can be made with it.

#### Solution

Given that,

Area of canvas ` 551m^2` and area of the canvas lost in wastage is `1m^2`

∴ area of canvas available for making the tent is `(551-1)m^2=550m^2.`

SA of tent =`550m^2` requiredïƒ— base radius of conical tent= 7m

CSA of tent=`550m^2 `

`pirl=550m^2`

`⇒22/7xx7xxl=550`

`⇒l=550/22=25m `

Now, WKT

`l^2=r^2+h^2`

`⇒(25)^2-(7)^2=h^2 `

`⇒ h=sqrt(625-49)`

`=sqrt576=24m`

So, the volume of the conical tent =`1/3pir^2h`

`= 1/3xx3.14xx(7xx7)(24)m^3=1232m^3`

Is there an error in this question or solution?

Solution for question: Monica Has a Piece of Canvas Whose Area is 551 M2. She Uses It to Have a Conical Tent Made, With a Base Radius of 7m. Assuming that All the Stitching Margins and Wastage Incurred While Cutting, Amou concept: Surface Area of a Right Circular Cone. For the course CBSE