#### Question

The dimensions of a rectangular box are in the ratio of 2 : 3 : 4 and the difference between the cost ofcovering it with sheet of paper at the rates of Rs. 8 and Rs. 9.50 per m2 is Rs.1248. Find the dimensions of the box.

#### Solution

Let the ratio be x

∴length = 2x

Breath = 3x

Height = 4x

∴Total surface area = `2[lb+bh+hl]`

`=2[6x^2+12x^2+8x^2]`

`=52x^2m^2`

When cost is at `Rs. 9.51 per m^2`

`∴Total cost of 52x^2m^2=Rs.8xx52x^2`

`= Rs. 416x^2`

And when the cost is at `95 per m^2`

`∴Total cost of 52x^2m^2=Rs.9.5xx52x^2`

`=Rs.499x^2`

`∴"different in cost"= Rs.494x^2-Rs.416x^2`

`⇒1248=494x^2-416x^2`

`⇒78x^2=1248`

`⇒x^2=16`

`⇒x=4`

Is there an error in this question or solution?

Solution The Dimensions of a Rectangular Box Are in the Ratio of 2 : 3 : 4 and the Difference Between the Cost Ofcovering It with Sheet of Paper at the Rates of Rs. 8 and Rs. 9.50 per M2 is Rs.1248. Concept: Surface Area of a Cuboid and a Cube.