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Solution for Ravish Wanted to Make a Temporary Shelter for His Car by Making a Box-like Structure with Tarpaulin that Covers All the Four Sides and the Top of the Car - CBSE Class 9 - Mathematics

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Question

Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of the car ( with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m with
base dimensions 4 m × 3m?

Solution

Given that

Shelter length = 4m
Breadth = 3m
Height = 2.5m
The tarpaulin will be required for four sides of the shelter

Area of tarpaulin in required`=2(lb+bh+hl)`

`=[2(4)xx2.5+(3xx2.5)+4xx3]m^2`

`=[2(10+7.5)+12]m^2`

`47m^2=47m^2`

  Is there an error in this question or solution?

APPEARS IN

 R.D. Sharma Mathematics for Class 9 by R D Sharma (2018-19 Session) (with solutions)
Chapter 18: Surface Areas and Volume of a Cuboid and Cube
Q: 13
Solution for question: Ravish Wanted to Make a Temporary Shelter for His Car by Making a Box-like Structure with Tarpaulin that Covers All the Four Sides and the Top of the Car concept: Surface Area of a Cuboid and a Cube. For the course CBSE
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