#### Question

Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of the car ( with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m with

base dimensions 4 m × 3m?

#### Solution

Given that

Shelter length = 4m

Breadth = 3m

Height = 2.5m

The tarpaulin will be required for four sides of the shelter

Area of tarpaulin in required`=2(lb+bh+hl)`

`=[2(4)xx2.5+(3xx2.5)+4xx3]m^2`

`=[2(10+7.5)+12]m^2`

`47m^2=47m^2`

Is there an error in this question or solution?

Solution Ravish Wanted to Make a Temporary Shelter for His Car by Making a Box-like Structure with Tarpaulin that Covers All the Four Sides and the Top of the Car Concept: Surface Area of a Cuboid and a Cube.