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# A Closed Iron Tank 12 M Long, 9 M Wide and 4 M Deep is to Be Made. Determine the Cost of Iron Sheet Used at the Rate of Rs. 5 per Metre Sheet, Sheet Being 2 M Wide. - CBSE Class 9 - Mathematics

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ConceptSurface Area of a Cuboid and a Cube

#### Question

A closed iron tank 12 m long, 9 m wide and 4 m deep is to be made. Determine the cost of iron sheet used at the rate of Rs. 5 per metre sheet, sheet being 2 m wide.

#### Solution

Given length =12,m  Breadth = 9m and Height =  4m.

Total surface area of tank=2(lb+bh+hl)

=2[12xx9+9xx4+12xx4]

=2[108+36+48]

=384m^2

"Now length of iron sheet"=(384)/("width of iron sheet" )

=384/2=194m.

Cost of iron sheet = length of sheet xx cost rate

=192xx5=Rs.960

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for Mathematics for Class 9 by R D Sharma (2018-19 Session) (2018 to Current)
Chapter 18: Surface Areas and Volume of a Cuboid and Cube
Ex.18.10 | Q: 11 | Page no. 14
Solution A Closed Iron Tank 12 M Long, 9 M Wide and 4 M Deep is to Be Made. Determine the Cost of Iron Sheet Used at the Rate of Rs. 5 per Metre Sheet, Sheet Being 2 M Wide. Concept: Surface Area of a Cuboid and a Cube.
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