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# Solution for A Tent of Height 77dm is in the Form a Right Circular Cylinder of Diameter 36m and Height 44dm Surmounted by a Right Circular Cone. Find the Cost of Canvas at Rs.3.50 per 2 M ? - CBSE Class 10 - Mathematics

ConceptSurface Area of a Combination of Solids

#### Question

A tent of height 77dm is in the form a right circular cylinder of diameter 36m and height 44dm surmounted by a right circular cone. Find the cost of canvas at Rs.3.50 per 2 m ?

#### Solution

Given that height of a tent = 77dm

Height of cone = 44dm

Height of a tent without cone = 77 - 44 = 33dm

= 3.3m

Given diameter of cylinder (d) = 36m

Radius (r) = 36/2= 18m

Let ‘l’ be slant height of cone

l^2=r^2+h^2

l^2=18^2+3.3^2

l2 = 324 + 10.89

l2 = 334.89

l = 18.3

Slant height of cone l = 18.3

Curved surface area of cylinder (S1) = 2πrh

= 2 x π x18 x 4.4m2          ............(1)

Curved surface area of cone (S2) =  πrl

=  π18 x 18.3m2              .............(2)

Total curved surface of tent = S1 + S2

T.C.S.A = S1 + S2

= 1532.46m2

Given cost canvas per m2 = RS 3.50

Total cost of canvas per 1532.46 X 3.50

= 1532.46 X 3.50

= 5363.61

∴ Total cost of canvas = Rs 5363.61

Is there an error in this question or solution?

#### APPEARS IN

RD Sharma Solution for 10 Mathematics (2018 to Current)
Chapter 14: Surface Areas and Volumes
Q: 30

#### Video TutorialsVIEW ALL [3]

Solution A Tent of Height 77dm is in the Form a Right Circular Cylinder of Diameter 36m and Height 44dm Surmounted by a Right Circular Cone. Find the Cost of Canvas at Rs.3.50 per 2 M ? Concept: Surface Area of a Combination of Solids.
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