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# Solution - 504 cones, each of diameter 3.5 cm and height 3 cm, are melted and recast into a metallic sphere. Find the diameter of the sphere and hence find its surface area. - CBSE Class 10 - Mathematics

ConceptSurface Area of a Combination of Solids

#### Question

504 cones, each of diameter 3.5 cm and height 3 cm, are melted and recast into a metallic sphere. Find the diameter of the sphere and hence find its surface area.
[Use π=22/7]

#### Solution

No. of cones = 504
Diameter of a cone = 3.5 cm
Radius of the cone, r = 1.75 cm
Height of the cone, h = 3 cm
Volume of a cone

=1/3pir^2h

=1/3xxpixx(3.5/2)^2xx3

=1/3xxpixx3.5/2xx3.5/2xx3  " cm"^2

Volume of 504 cones

=504xx1/3xxpixx3.5/2xx3.5/2xx3  " cm"^2

Let the radius of the new sphere be ‘R’.
Volume of the sphere =4/3 pir^3
Volume of 504 cones = Volume of the sphere

504xx1/3xxpixx3.5/2xx3.5/2xx3=4/3 piR^3

(504xx1xxpixx3.5xx3.5xx3xx3)/(3xx2xx2xx4xxpi)=R^3

R^3=(504xx3xx49)/64

R^3=(8xx27xx7^3)/64

R=(2xx3xx7)/4

R=21/2=10.5 cm

Radius of the new sphere = 10.5 cm

Is there an error in this question or solution?

#### Reference Material

Solution for question: 504 cones, each of diameter 3.5 cm and height 3 cm, are melted and recast into a metallic sphere. Find the diameter of the sphere and hence find its surface area. concept: Surface Area of a Combination of Solids. For the course CBSE
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