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Sunita is Twice as Old as Ashima. If Six Years is Subtracted from Ashima'S Age and Four Years Added to Sunita'S Age, Then Sunita Will Be Four Times Ashima'S Age. How Old Were They Two Years Ago? - Mathematics

Numerical

Sunita is twice as old as Ashima. If six years is subtracted from Ashima's age and four years added to Sunita's age, then Sunita will be four times Ashima's age. How old were they two years ago?

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Solution

Let the age of Ashima be x years . 
Therefore, the age of Sunita will be 2x years . 
According to the question, 
4(x - 6) = 2x + 4
or 4x - 24 = 2x + 4
or 4x - 2x = 4 + 24
or 2x = 28
or x = 14
∴Age of Ashima = 14 years . 
 Age of Sunita = 2 x 14 = 28 years .

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APPEARS IN

RD Sharma Class 8 Maths
Chapter 9 Linear Equation in One Variable
Exercise 9.4 | Q 11 | Page 30
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