Solution - Sum of First n Terms of an AP

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ConceptSum of First n Terms of an AP

Question

The houses in a row numbered consecutively from 1 to 49. Show that there exists a value of X such that sum of numbers of houses preceding the house numbered X is equal to sum of the numbers of houses following X.

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The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.

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Find the sum of the following APs.

0.6, 1.7, 2.8 ,…….., to 100 terms

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If the ratio of the sum of first n terms of two A.P’s is (7n +1): (4n + 27), find the ratio of their mth terms.

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The sum of the first p, q, r terms of an A.P. are a, b, c respectively. Show that \frac { a }{ p } (q – r) + \frac { b }{ q } (r – p) + \frac { c }{ r } (p – q) = 0

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The first and the last terms of an AP are 8 and 65 respectively. If the sum of all its terms is 730, find its common difference.

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Reference Material

Solution for concept: Sum of First n Terms of an AP. For the course 8th-10th CBSE
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