#### Question

In an AP

Given a = 3, n = 8, S = 192, find d.

#### Solution

Given that, *a* = 3, *n* = 8, *S* = 192

`S_n = n/2[2a+(n-1)d]`

`192 = 8/2[2xx3+(8-1)d]`

192 = 4 [6 + 7*d*]

48 = 6 + 7*d*

42 = 7*d*

*d = *6

Is there an error in this question or solution?

Solution In an AP Given A = 3, N = 8, S = 192, Find d. Concept: Sum of First n Terms of an AP.