CBSE Class 10CBSE
Share
Notifications

View all notifications

In an AP Given A = 3, N = 8, S = 192, Find d. - CBSE Class 10 - Mathematics

Login
Create free account


      Forgot password?

Question

 In an AP

Given a = 3, n = 8, S = 192, find d.

Solution

Given that, a = 3, n = 8, S = 192

`S_n = n/2[2a+(n-1)d]`

`192 = 8/2[2xx3+(8-1)d]`

192 = 4 [6 + 7d]

48 = 6 + 7d

42 = 7d

d = 6

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 10 (2019 to Current)
Chapter 5: Arithmetic Progressions
Ex.5.30 | Q: 3.09 | Page no. 112
Solution In an AP Given A = 3, N = 8, S = 192, Find d. Concept: Sum of First n Terms of an AP.
S
View in app×