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Find the Sum of First 40 Positive Integers Divisible by 6. - CBSE Class 10 - Mathematics

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Question

Find the sum of first 40 positive integers divisible by 6.

Solution

The positive integers that are divisible by 6 are

6, 12, 18, 24 …

It can be observed that these are making an A.P. whose first term is 6 and common difference is 6.

a = 6

d = 6

S40 =?

The positive integers that are divisible by 6 are

6, 12, 18, 24 …

It can be observed that these are making an A.P. whose first term is 6 and common difference is 6.

a = 6

d = 6

S40 =?

`S_n = n/2[2a+(n-1)d]`

`S_40 = 40/2[2(6)+(40-1)6]`

= 20[12 + (39) (6)]

= 20(12 + 234)

= 20 × 246

= 4920

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 10 (2019 to Current)
Chapter 5: Arithmetic Progressions
Ex. 5.30 | Q: 12 | Page no. 113
Solution Find the Sum of First 40 Positive Integers Divisible by 6. Concept: Sum of First n Terms of an AP.
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