#### Question

Find (a) the total number and (b) the total mass of neutrons in 7 mg of ^{14}C.

(Assume that mass of a neutron = 1.675 × 10^{–27} kg).

#### Solution

ii (a) Number of atoms of ^{14}C in 1 mole= 6.023 × 10^{23}

Since 1 atom of ^{14}C contains (14 – 6) i.e., 8 neutrons, the number of neutrons in 14 g of ^{14}C is (6.023 × 10^{23}) ×8. Or, 14 g of ^{14}C contains (6.022 × 10^{23} × 8) neutrons.

Number of neutrons in 7 mg

= (6.022 xx 10^(23)xx8xx7 "mg")/(1400 "mg")`

= 2.4092 × 10^{21}

Is there an error in this question or solution?

Solution Find (A) the Total Number and (B) the Total Mass of Neutrons in 7 Mg Of 14c Concept: Subatomic Particles - Discovery of Protons and Neutrons.