Study the extract of Survey of India Map Sheet No. 45D/7 and answer the following questions.
(a) What do you understand by Eastings and Northings?
(b) Give the meaning of each of the following conventional symbols located in the grid square 1622.
(i) 20r (ii) PO
(c) What is the general direction of flow of the Sipu Nadi, given in the map extract? Give one reason to support your answer.
(d) Give the six-figure grid reference of:
(i) The point where the canal leaves the earth work, dam market 10r.
(ii) The spot height 1425 in the South-east corner of the map extract.
(e) Andhra is a better developed settlement than Gulabganj. Give two reasons.
(f) Account for the necessity of ‘fireline’ in the jungle area of the given map extract.
(i) What main purpose is solved by most of the wells in grid square 1621?
(ii) Why is the water in some of these wells not suitable for drinking?
(h) Name two probable occupations of the people in the settlement of Tokra in squares 2220 and 2221.
(i) What is the total length of canal in metres?
(j) Give the angular distance of the temple in Pithapura in 2022 from Bhumi Margi hill top.
(a) They are grid lines marked in red on the topo maps. The lines running vertically are called Eastings and those running horizontally are called Northings.
(i) 20r means that the relative depth of water level in the well is 20m.
(ii) PO is the conventional sign for the Post Office.
(c) East to south-west. It is evident from the decreasing value of the spot heights.
(d) (i) 223214 (ii) 236142
(i) Andhra is connected by a telephone line and Ghlabganj is not.
(ii) Andhra has a Post and Telegraph Office and Dak Bungalow.
(f) Fireline is clearing of 5 m in the forest to control the spread of forest fire. In the hot dry season these forests often suffer from severe problem of forest fire.
(i) The Brackish well in 1621 has saline water which is used for lime stock and washing purpose.
(ii) Due to large amount of dissolved salts the water is unfit for drinking.
(h) Cultivation and management of the reservoir.
(i) 12.5 cm/2 = 6.25 km.
(j) N140 W.