HSC Commerce 12th Board ExamMaharashtra State Board
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Solution for Find Karl Pearson'S Correlation Coefficient for the Following Data : - HSC Commerce 12th Board Exam - Mathematics and Statistics

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Question

Find Karl Pearson's correlation coefficient for the following data : 

X 3 2 1 5 4
Y 8 4 10 2 6

Solution

`X` `Y` `X^2` `Y^2` `xy`
3 8 9 64 24
2 4 4 16 8
1 10 1 100 10
5 2 25 4 10
4 6 16 36 24
15 30 55 220 76

Here n =`5,∑x=15,∑y=30,∑x^2=55,∑y^2=220,∑xy=76` 

Karl pearson coefficient of correlation between x
and y is 

`r(x,y)= (n∑xy-∑x∑y)/(sqrt(n∑x^2-(∑x)^2)sqrt(n∑y^2-(∑y)^2))` 

=` (5xx76-15xx30)/(sqrt(5xx55-(15)^2) sqrt(5xx220-(30)^2))` 

= `(380-450)/(sqrt(275-225)sqrt(1100-900))`  

=`(-70)/(sqrt(50) sqrt(200))` 

=`(-70)/100=-0.7` 

  Is there an error in this question or solution?

APPEARS IN

 2017-2018 (March) (with solutions)
Question 5.2.2 | 4.00 marks
Solution Find Karl Pearson'S Correlation Coefficient for the Following Data : Concept: Statistics - Karl Pearson’s Coefficient of Correlation.
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