#### Question

A clock regulated by seconds pendulum, keeps correct time. During summer, length of pendulum increases to 1.005 m. How much will the clock gain or loose in one day?

(g = 9.8 m/s^{2} and π = 3.142)

#### Solution

Given: L = 1.005 m, g = 9.8 m/s^{2}

To find: Loss in period (ΔT)

Formula: `T=2pisqrt(L/g)`

`T=2xx3.14xxsqrt(1.005/9.8)`

`=2.012 s`

The period of a seconds pendulum is 2 second.

Hence, the given pendulum clock will lose 0.012s in 2.012s (during summer).

Loss in period per day

`ΔT=(24xx3600xx0.012)/2.012`

`DeltaT=515.3s`

The clock will gain or lose 515.3 s in one day.

Is there an error in this question or solution?

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A Clock Regulated by Seconds Pendulum, Keeps Correct Time. During Summer, Length of Pendulum Increases to 1.005 M. How Much Will the Clock Gain Or Loose in One Day? Concept: Some Systems Executing Simple Harmonic Motion.

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