Some measures are given in the adjacent figure, find the area of ☐ABCD.
Area of Δ BDC = `1/2 xx 13 xx 60` = 390 m²
Area of Δ BAD = `1/2 xx` AB X AD = `1/2 xx 40 xx 9` = 180 m²
Area of ☐ABCD = Ar of Δ BDC + Ar of Δ BAD
= 390 + 180
= 570 m²
Is there an error in this question or solution?
Solution Some Measures Are Given in the Adjacent Figure, Find the Area of ☐Abcd. Concept: Area of a Triangle by Heron’S Formula.