# Solve X(X + 1) + (X + 2)(X + 3) = 42 - Mathematics

Sum

Solve x(x + 1) + (x + 2)(x + 3) = 42

#### Solution

x(x + 1) + (x + 2)(x + 3) = 42

=> x^2 + x + x^2 + 3x + 2x + 6 - 42 = 0

=> 2x^2 + 6x - 36 = 0

=> 2x^2 + 12x - 6x - 36 = 0

=> 2x(x + 6) - 6(x + 6) = 0

=> (x + 6)(2x - 6) = 0

if x + 6 = 0 or 2x - 6 = 0

then x = -6 or x = 3

Is there an error in this question or solution?

#### APPEARS IN

Selina Concise Maths Class 10 ICSE