Maharashtra State BoardHSC Science (Electronics) 11th
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Solve the numerical example. When the planet Jupiter is at a distance of 824.7 million kilometers from the Earth, its angular diameter is measured to be 35.72'' of arc. - Physics

Numerical

Solve the numerical example.

When the planet Jupiter is at a distance of 824.7 million kilometers from the Earth, its angular diameter is measured to be 35.72'' of arc. Calculate the diameter of Jupiter.

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Solution

Given: Angular diameter (α) = 35.72''

= 35.72'' × 4.847 × 10-6 rad

≈ 1.73 × 10-4 rad

Distance from Earth (D) = 824.7 million km

= 824.7 × 106 km

= 824.7 × 109 m.

To find: Diameter of Jupiter (d)

Formula: d = α D

Calculation: From the formula,

d = 1.73 × 10-4 × 824.7 × 109

= 1.428 × 108 m

= 1.428 × 105 km

The diameter of Jupiter is 1.428 × 105 km.

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APPEARS IN

Balbharati Physics 11th Standard Maharashtra State Board
Chapter 1 Units and Measurements
Exercises | Q 3. (xiii) | Page 15
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