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Solve the numerical example. Find the percentage error in kinetic energy of a body having mass 60.0 ± 0.3 g moving with a velocity of 25.0 ± 0.1 cm/s. - Physics

Numerical

Solve the numerical example.

Find the percentage error in kinetic energy of a body having mass 60.0 ± 0.3 g moving with a velocity of 25.0 ± 0.1 cm/s.

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Solution

Given: m = 60.0 g, v = 25.0 cm/s, Δm = 0.3 g, Δv = 0.1 cm/s

To find: Percentage error in E

Formula: Percentage error in E

`= ((triangle"m")/"m" + 2 (triangle"v")/"v") xx 100%`

Calculation: From formula,

Percentage error in E = `(0.3/60.0 + 2 xx 0.1/25.0) xx 100%`

= 1.3 %

The percentage error in energy is 1.3%.

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APPEARS IN

Balbharati Physics 11th Standard Maharashtra State Board
Chapter 1 Units and Measurements
Exercises | Q 3. (vii) | Page 14
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