Numerical
Solve the numerical example.
Find the percentage error in kinetic energy of a body having mass 60.0 ± 0.3 g moving with a velocity of 25.0 ± 0.1 cm/s.
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Solution
Given: m = 60.0 g, v = 25.0 cm/s, Δm = 0.3 g, Δv = 0.1 cm/s
To find: Percentage error in E
Formula: Percentage error in E
`= ((triangle"m")/"m" + 2 (triangle"v")/"v") xx 100%`
Calculation: From formula,
Percentage error in E = `(0.3/60.0 + 2 xx 0.1/25.0) xx 100%`
= 1.3 %
The percentage error in energy is 1.3%.
Concept: Errors in Measurements
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