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Solve the inequation `("2x" + 1)/3 + 15 ≤ 17;` x ∈ W.

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#### Solution

`("2x" + 1)/3 + 15 ≤ 17`; x ∈ W

`=> ("2x" + 1)/3 ≤ 17 - 15 = 2`

⇒ 2x + 1 ≤ 6

⇒ 2x ≤ 5

⇒ x ≤ `5/2 = 2 1/2`

But x ∈ W

∴ x = 0, 1, 2

∴ Solution set is = {0, 1, 2}

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